Barber Colman 6-10 feed gearing calculations


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Posted by David Hollinger on April 05, 2007 at 13:09:57:

I have a question. We have several Barber Colman 6-10 machines. They are machine constants of K=8, K=12, K=18, K=24. When we calculate the feed gears for helical gears, for all machines except the k=18 we use this formula:
Pn/(C*Sine of helix angle)*12/K = feed rate in/rev
This does not work for the K=18 machines. For those machines we have to use this equation:
Pn/(C*Sine of helix angle)= feed rate in/rev
Does anybody know why they are different? The Barber Colman book shows the equation without the 12/K portion, but that gives us gears with NO teeth on the K=8 and K=24. Very curious why the different equations work.
David Hollinger


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